360=4x^2+14x-8

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Solution for 360=4x^2+14x-8 equation:



360=4x^2+14x-8
We move all terms to the left:
360-(4x^2+14x-8)=0
We get rid of parentheses
-4x^2-14x+8+360=0
We add all the numbers together, and all the variables
-4x^2-14x+368=0
a = -4; b = -14; c = +368;
Δ = b2-4ac
Δ = -142-4·(-4)·368
Δ = 6084
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{6084}=78$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-14)-78}{2*-4}=\frac{-64}{-8} =+8 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-14)+78}{2*-4}=\frac{92}{-8} =-11+1/2 $

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